How to copy an array in Bash?

Question

I have an array of applications, initialized like this:

depends=$(cat ~/Depends.txt)

When I try to parse the list and copy it to a new arra

Answer 1

You can copy an array by inserting the elements of the first array into the copy by specifying the index:

#!/bin/bash

array=( One Two Three Go! );
array_copy( );

let j=0;
for (( i=0; i<${#array[@]}; i++)
do
    if [[ $i -ne 1 ]]; then # change the test here to your 'isn't installed' test
        array_copy[$j]="${array[$i]}
        let i+=1;
    fi
done

for k in "${array_copy[@]}"; do
    echo $k
done

The output of this would be:

One
Three
Go!

A useful document on bash arrays is on TLDP.