Copy table structure to new table in sqlite3

Question

Is there an easy way to copy an existing table structure to a new one? (dont need the data, only the structure -> like id INTEGER, name varchar(20) ...)

Thx

Answer 1

I would prefer :

> sqlite3 

sqlite3 > .output 
sqlite3 > .dump 

The line above generates the dump of table that includes DDL and DML statement.

Make changes in this file, i.e. find and replace the table name with new table name

Also, replace "CREATE TRIGGER " with "CREATE TRIGGER _" , this will replace existing triggers with trigger names with a new table name on it. That will make it unique and will not cause conflicts with existing triggers. Once all schema changes are implemented, read it back into database using .read

sqlite3 > .read output_file

This can be scripted in shell file using shell commands like :

echo ".dump " | sqlite3  > 
sed -i.bak "s/\b\b//g" 
sed -i.bak "s/\bCREATE TRIGGER \b/CREATE TRIGGER /g" 
echo ".read " | sqlite3 
rm .bak 


For example :

If you have table T and new table is TClone in db file D with file F to be created : then 

echo ".dump T" | sqlite3 D.sqlite > F
sed -i.bak "s/\bT\b/TClone/g" F
sed -i.bak "s/\bCREATE TRIGGER \b/CREATE TRIGGER TClone_>/g" F
echo ".read F" | sqlite3 D.sqlite 
rm T.bak


Finally, you can generalize this script by creating a parameterized version where you can pass source_table, destination_table , db_file as parameters that can be used to clone any table.

I tested this and it works.

Testing :

sqlite3 
sqlite3 > select * from ;


should give you same results as original table. and 

sqlite3 > .schema 


should have same schema as that of original table with a new name.
    

             

                                                        
            
            

              
                
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