Python split list into n chunks

Question

I know this question has been covered many times but my requirement is different.

I have a list like: range(1, 26). I want to divide this list into a fi

Answer 1

more_itertools.divide is one approach to solve this problem:

import more_itertools as mit


iterable = range(1, 26)
[list(c) for c in mit.divide(6, iterable)]

Output

[[ 1,  2,  3,  4, 5],                       # remaining item
 [ 6,  7,  8,  9],
 [10, 11, 12, 13],
 [14, 15, 16, 17],
 [18, 19, 20, 21],
 [22, 23, 24, 25]]

As shown, if the iterable is not evenly divisible, the remaining items are distributed from the first to the last chunk.

See more about the more_itertools library here.