How to split a sequence into two pieces by predicate?

Question

How do I split a sequence into two lists by a predicate?

Alternative: I can use filter and filterNot, or write my own method, but isn\'t th

Answer 1

If you want to split a list into more than 2 pieces, and ignore the bounds, you could use something like this (modify if you need to search for ints)

def split(list_in: List[String], search: String): List[List[String]] = {
  def split_helper(accum: List[List[String]], list_in2: List[String], search: String): List[List[String]] = {
    val (h1, h2) = list_in2.span({x: String => x!= search})
    val new_accum = accum :+ h1
    if (h2.contains(search)) {
      return split_helper(new_accum, h2.drop(1), search) 
    }
    else {
    return accum
    }
  }
  return split_helper(List(), list_in, search)
}

// TEST

// split(List("a", "b", "c", "d", "c", "a"), {x: String => x != "x"})