If list index exists, do X

Question

In my program, user inputs number n, and then inputs n number of strings, which get stored in a list.

I need to code such that if a certain

Answer 1

Oneliner:

do_X() if len(your_list) > your_index else do_something_else()  

Full example:

In [10]: def do_X(): 
    ...:     print(1) 
    ...:                                                                                                                                                                                                                                      

In [11]: def do_something_else(): 
    ...:     print(2) 
    ...:                                                                                                                                                                                                                                      

In [12]: your_index = 2                                                                                                                                                                                                                       

In [13]: your_list = [1,2,3]                                                                                                                                                                                                                  

In [14]: do_X() if len(your_list) > your_index else do_something_else()                                                                                                                                                                      
1

Just for info. Imho, try ... except IndexError is better solution.