How to optimally divide an array into two subarrays so that sum of elements in both are same, otherwise give an error?

Question

How to optimally divide an array into two subarrays so that sum of elements in both subarrays is same, otherwise give an error?

Example 1

Given the array

Answer 1

public class Problem1 {

public static void main(String[] args) throws IOException{
    Scanner scanner=new Scanner(System.in);
    ArrayList array=new ArrayList();
    int cases;
    System.out.println("Enter the test cases");
    cases=scanner.nextInt();

    for(int i=0;i array){
    boolean flag=false;
    Collections.sort(array);
    System.out.println(array);
    int index=array.size();

    ArrayList sub1=new ArrayList();
    ArrayList sub2=new ArrayList();

    sub1.add(array.get(index-1));
    array.remove(index-1);

    index=array.size();
    sub2.add(array.get(index-1));
    array.remove(index-1);

    while(!array.isEmpty()){

    if(compareSum(sub1,sub2)){
        index=array.size();
        sub2.add(array.get(index-1));
        array.remove(index-1);
    }
    else{
        index=array.size();
        sub1.add(array.get(index-1));
        array.remove(index-1);
    }   
    }

    if(sumOfArray(sub1).equals(sumOfArray(sub2)))
        flag=true;
    else
        flag=false;

    return flag;
}

public static Integer sumOfArray(ArrayList array){
    Iterator it=array.iterator();
    Integer sum=0;
    while(it.hasNext()){
        sum +=it.next();
    }

    return sum;
}

public static boolean compareSum(ArrayList sub1,ArrayList sub2){
    boolean flag=false;

    int sum1=sumOfArray(sub1);
    int sum2=sumOfArray(sub2);

    if(sum1>sum2)
        flag=true;
    else
        flag=false;

    return flag;
}

}

// The Greedy approach //