Imagine a directed acyclic graph as follows, where:
I am proposing O(|V| + |E|) time complexity solution, and i think this approach is correct otherwise please correct me.
Given directed acyclic graph, we need to find LCA of two vertices v and w.
Step1: Find shortest distance of all vertices from root vertex using bfs http://en.wikipedia.org/wiki/Breadth-first_search with time complexity O(|V| + |E|) and also find the parent of each vertices.
Step2: Find the common ancestors of both the vertices by using parent until we reach root vertex Time complexity- 2|v|
Step3: LCA will be that common ancestor which have maximum shortest distance.
So, this is O(|V| + |E|) time complexity algorithm.
Please, correct me if i am wrong or any other suggestions are welcome.