Better way to generate array of all letters in the alphabet

Question

Right now I\'m doing

for (char c = \'a\'; c <= \'z\'; c++) {
    alphabet[c - \'a\'] = c;
}

but is there a better way to do it? Similar

Answer 1

char[] abc = new char[26];

for(int i = 0; i<26;i++) {
    abc[i] = (char)('a'+i);
}