Better way to generate array of all letters in the alphabet

Question

Right now I\'m doing

for (char c = \'a\'; c <= \'z\'; c++) {
    alphabet[c - \'a\'] = c;
}

but is there a better way to do it? Similar

Answer 1

This is a fun Unicode solution.

char[] alpha = new char[26]
for(int i = 0; i < 26; i++){
    alpha[i] = (char)(97 + i)
}

This generates a lower-cased version of alphabet, if you want upper-cased, you can replace '97' with '65'.

Hope this helps.