Better way to generate array of all letters in the alphabet

Question

Right now I\'m doing

for (char c = \'a\'; c <= \'z\'; c++) {
    alphabet[c - \'a\'] = c;
}

but is there a better way to do it? Similar

Answer 1

char[] alphabet = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};