C++11 way to index tuple at runtime without using switch

Question

I have a piece of c++11 code similar like below:

switch(var) {
   case 1: dosomething(std::get<1>(tuple));
   case 2: dosomething(std::get<2>(tup         


        

Answer 1

For c++11 here is a concise approach that returns a pointer:

template ::value>
struct tuple_address {
  static void * of(Tuple & tuple, long function_index) {
    if (template_index - 1 == function_index) {
      return &std::get(tuple);
    } else {
      return tuple_address::of(tuple, function_index);
    }
  }
};
template 
struct tuple_address {
  static void * of(Tuple & tuple, long function_index) {
    return 0;
  }
};
template 
void * tuple_address_of(Tuple & tuple, long index) {
  return tuple_address::of(tuple, index);
}