how to pass parameters of a function when using timeit.Timer()

Question

This is the outline of a simple program

# some pre-defined constants
A = 1
B = 2

# function that does something critical
def foo(num1, num2):
    # do somet         


        

Answer 1

I was playing around with timing in Python 3.7 today and trying to pass functions and variables into the timer. This is what I came up with.

import re

text = "This         is      a  test of the      emergency broadcast       system"

def regex(text):
    return re.sub(r"(\s)\1{1,}", r"\1", text)

def loop_while(text):
    if "  " in text:
        while "  " in text:
            text = text.replace("  ", " ")

    return text

if __name__ == "__main__":
    import timeit

    callable_functions = [item for item in locals().items() if callable(item[1])]

    for func_name, func in callable_functions:
        elapsed_time = timeit.timeit(f"{func_name}(text)", globals=globals(), number=100000)
        print(f"{func_name}: {elapsed_time} \n{func(text)}\n")

This outputs:

regex: 1.378352418
This is a test of the emergency broadcast system

loop_while: 0.15858950299999997
This is a test of the emergency broadcast system

Then all it takes to test a new version is adding in a new function. Something like:

def split_join(text):
    return " ".join(text.split())

Now it outputs:

regex: 1.378352418
This is a test of the emergency broadcast system

loop_while: 0.15858950299999997
This is a test of the emergency broadcast system

split_join: 0.05700970800000005
This is a test of the emergency broadcast system