how to pass parameters of a function when using timeit.Timer()

Question

This is the outline of a simple program

# some pre-defined constants
A = 1
B = 2

# function that does something critical
def foo(num1, num2):
    # do somet         


        

Answer 1

This should work:

import timeit

def f(x,y):
    return x*y

x = 5
y = 7

print(timeit.timeit(stmt='f(x,y)',
                    setup='from __main__ import f, x, y',
                    number=1000))