Implementing the decorator pattern in Python

Question

I want to implement the decorator pattern in Python, and I wondered if there is a way to write a decorator that just implements the function it wants to modify, without writ

Answer 1

As an addendum to Philipp's answer; if you need to not only decorate, but preserve the type of an object, Python allows you to subclass an instance at runtime:

class foo(object):
    def f1(self):
        print "original f1"

    def f2(self):
        print "original f2"


class foo_decorator(object):
    def __new__(cls, decoratee):
        cls = type('decorated',
                   (foo_decorator, decoratee.__class__),
                   decoratee.__dict__)
        return object.__new__(cls)

    def f1(self):
        print "decorated f1"
        super(foo_decorator, self).f1()


u = foo()
v = foo_decorator(u)
v.f1()
v.f2()
print 'isinstance(v, foo) ==', isinstance(v, foo)

This is a bit more involved than strictly necessary for your example, where you know the class being decorated in advance.

This might suffice:

class foo_decorator(foo):
    def __init__(self, decoratee):
        self.__dict__.update(decoratee.__dict__)

    def f1(self):
        print "decorated f1"
        super(foo_decorator, self).f1()