PyQt: Show menu in a system tray application

Question

First of all, I\'m an experienced C programmer but new to python. I want to create a simple application in python using pyqt. Let\'s imagine this application it is as simple

Answer 1

I couldn't get any of the above answers to work in PyQt5 (the exit in the system tray menu, wouldn't actually exit), but i managed to combine them for a solution that does work. I'm still trying to determine if exitAction should be used further somehow.

import sys
from PyQt5 import QtWidgets, QtCore, QtGui

class SystemTrayIcon(QtWidgets.QSystemTrayIcon):

    def __init__(self, icon, parent=None):
        QtWidgets.QSystemTrayIcon.__init__(self, icon, parent)
        menu = QtWidgets.QMenu(parent)
        exitAction = menu.addAction("Exit")
        self.setContextMenu(menu)
        menu.triggered.connect(self.exit)

    def exit(self):
        QtCore.QCoreApplication.exit()

def main(image):
    app = QtWidgets.QApplication(sys.argv)
    w = QtWidgets.QWidget()
    trayIcon = SystemTrayIcon(QtGui.QIcon(image), w)
    trayIcon.show()
    sys.exit(app.exec_())


if __name__ == '__main__':
    on='icon.ico'
    main(on)