What's the simplest way to subtract a month from a date in Python?

Question

If only timedelta had a month argument in it\'s constructor. So what\'s the simplest way to do this?

EDIT: I wasn\'t thinking too hard about this as was poin

Answer 1

You can use below given function to get date before/after X month.

from datetime import date

def next_month(given_date, month):
    yyyy = int(((given_date.year * 12 + given_date.month) + month)/12)
    mm = int(((given_date.year * 12 + given_date.month) + month)%12)

    if mm == 0:
        yyyy -= 1
        mm = 12

    return given_date.replace(year=yyyy, month=mm)


if __name__ == "__main__":
    today = date.today()
    print(today)

    for mm in [-12, -1, 0, 1, 2, 12, 20 ]:
        next_date = next_month(today, mm)
        print(next_date)