Under what circumstances are C++ destructors not going to be called?

Question

I know that my destructors are called on normal unwind of stack and when exceptions are thrown, but not when exit() is called.

Are there any other cases where my des

Answer 1

A signal by itself won't affect the execution of the current thread and hence the invocation of destructors, because it is a different execution context with its own stack, where your objects do not exist. It's like an interrupt: it is handled somewhere outside of your execution context, and, if handled, the control is returned to your program.

Same as with multithreading, C++ the language does not know a notion of signals. These two are completely orthogonal to each other and are specified by two unrelated standards. How they interact is up to the implementation, as long as it does not break either of the standards.

As a side note, another case is when object's destructor won't be called is when its constructor throws an exception. Members' destructors will still be called, though.