First Python list index greater than x?

Question

What would be the most Pythonic way to find the first index in a list that is greater than x?

For example, with

list = [0.5, 0.3, 0.9, 0.8]
         


        

Answer 1

I know there are already plenty of answers, but I sometimes I feel that the word pythonic is translated into 'one-liner'.

When I think a better definition is closer to this answer:

"Exploiting the features of the Python language to produce code that is clear, concise and maintainable."

While some of the above answers are concise, I do not find them to be clear and it would take a newbie programmer a while to understand, therefore not making them extremely maintainable for a team built of many skill levels.

l = [0.5, 0.3, 0.9, 0.8]

def f(l, x):
    for i in l:
        if i >x: break
    return l.index(i)


f(l,.7)

or

l = [0.5, 0.3, 0.9, 0.8]

def f(l, x):
    for i in l:
        if i >x: return l.index(i)



f(l,.7)

I think the above is easily understood by a newbie and is still concise enough to be accepted by any veteran python programmer.

I think writing dumb code is a positive.