How does a Java HashMap handle different objects with the same hash code?

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余生分开走
余生分开走 2020-11-22 02:27

As per my understanding I think:

  1. It is perfectly legal for two objects to have the same hashcode.
  2. If two objects are equal (using the equals() method)
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  •  日久生厌
    2020-11-22 03:33

    You're mistaken on point three. Two entries can have the same hash code but not be equal. Take a look at the implementation of HashMap.get from the OpenJdk. You can see that it checks that the hashes are equal and the keys are equal. Were point three true, then it would be unnecessary to check that the keys are equal. The hash code is compared before the key because the former is a more efficient comparison.

    If you're interested in learning a little more about this, take a look at the Wikipedia article on Open Addressing collision resolution, which I believe is the mechanism that the OpenJdk implementation uses. That mechanism is subtly different than the "bucket" approach one of the other answers mentions.

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