Calling the base constructor in C#

Question

If I inherit from a base class and want to pass something from the constructor of the inherited class to the constructor of the base class, how do I do that?

For exa

Answer 1

Using newer C# features, namely out var, you can get rid of the static factory-method. I just found out (by accident) that out var parameter of methods called inse base-"call" flow to the constructor body.

Example, using this base class you want to derive from:

public abstract class BaseClass
{
    protected BaseClass(int a, int b, int c)
    {
    }
}

The non-compiling pseudo code you want to execute:

public class DerivedClass : BaseClass
{
    private readonly object fatData;

    public DerivedClass(int m)
    {
        var fd = new { A = 1 * m, B = 2 * m, C = 3 * m };
        base(fd.A, fd.B, fd.C); // base-constructor call
        this.fatData = fd;
    }
}

And the solution by using a static private helper method which produces all required base arguments (plus additional data if needed) and without using a static factory method, just plain constructor to the outside:

public class DerivedClass : BaseClass
{
    private readonly object fatData;

    public DerivedClass(int m)
        : base(PrepareBaseParameters(m, out var b, out var c, out var fatData), b, c)
    {
        this.fatData = fatData;
        Console.WriteLine(new { b, c, fatData }.ToString());
    }

    private static int PrepareBaseParameters(int m, out int b, out int c, out object fatData)
    {
        var fd = new { A = 1 * m, B = 2 * m, C = 3 * m };
        (b, c, fatData) = (fd.B, fd.C, fd); // Tuples not required but nice to use
        return fd.A;
    }
}