How to iterate over arguments in a Bash script

Question

I have a complex command that I\'d like to make a shell/bash script of. I can write it in terms of $1 easily:

foo $1 args -o $1.ext
         


        

Answer 1

You can also access them as an array elements, for example if you don't want to iterate through all of them

argc=$#
argv=("$@")

for (( j=0; j