Instantiating a case class from a list of parameters

Question

Given:

case class Foo(a: Int, b: String, c: Double)

you can say:

val params = Foo(1, \"bar\", 3.14).productIterator.toList
         


        

Answer 1

Another one liner using case class companion object curried method and completely ignoring type safety :)

scala> case class Foo(a: Int, b: String, c: Double)
defined class Foo

scala> val lst = List(1, "bar", 3.14)
lst: List[Any] = List(1, bar, 3.14)

scala> val foo = lst.foldLeft(Foo.curried: Any){case (r, v) => r.asInstanceOf[Function[Any, _]](v) }.asInstanceOf[Foo]
foo: Foo = Foo(1,bar,3.14)