How to break when a specific exception type is thrown in GDB?

Question

According to the documentation I can break on specific exception type by using conditional breakpoints. However the syntax for the condition isn\'t very clear to me:

Answer 1

I think I can answer the part about setting conditional breaks. I won't answer question regarding exceptions as __raise_exception seems to not exist in g++ 4.5.2 (?)

Let's assume that you have following code (I use void to get something similar to __raise_exception from gdb doc)

void foo(void* x) {

}

int main() {
    foo((void*)1);
    foo((void*)2);
}

to break at foo(2) you use following commands

(gdb) break foo
Breakpoint 1 at 0x804851c: file q.cpp, line 20.
(gdb) condition 1 x == 2

If you run with

(gdb) r

you will see that it stops on the second foo call, but not on the first one

I think, what they meant in docs is that you set break on function __raise_exception (very implementation dependent)

 /* addr is where the exception identifier is stored
    id is the exception identifier.  */
    void __raise_exception (void **addr, void *id);

and then set conditional break on id as described above (you have to somehow determine what is id for yours exception type).

Unfortunately

 (gdb) break __raise_exception

results with (g++ 4.5.2)

 Function "__raise_exception" not defined.