Why would I use dirname(__FILE__) in an include or include_once statement?

Question

I have seen this:

Why would I ever need to do th

Answer 1

Let's say I have a (fake) directory structure like:

.../root/
        /app
            bootstrap.php
        /scripts
            something/
                somescript.php
        /public
            index.php

Now assume that bootstrap.php has some code included for setting up database connections or some other kind of boostrapping stuff.

Assume you want to include a file in boostrap.php's folder called init.php. Now, to avoid scanning the entire include path with include 'init.php', you could use include './init.php'.

There's a problem though. That ./ will be relative to the script that included bootstrap.php, not bootstrap.php. (Technically speaking, it will be relative to the working directory.)

dirname(__FILE__) allows you to get an absolute path (and thus avoid an include path search) without relying on the working directory being the directory in which bootstrap.php resides.

(Note: since PHP 5.3, you can use __DIR__ in place of dirname(__FILE__).)

Now, why not just use include 'init.php';?

As odd as it is at first though, . is not guaranteed to be in the include path. Sometimes to avoid useless stat()'s people remove it from the include path when they are rarely include files in the same directory (why search the current directory when you know includes are never going to be there?).

Note: About half of this answer is address in a rather old post: What's better of require(dirname(__FILE__).'/'.'myParent.php') than just require('myParent.php')?