Can I make list_filter in django admin to only show referenced ForeignKeys?

Question

I have a django application which has two models like this:

class MyModel(models.Model):
    name = models.CharField()
    country = models.ForeignKey(\'Coun         


        

Answer 1

This is my take on a general and reusable implementation for Django 1.4, if you happen to be stuck at that version. It is inspired by the built-in version that is now part of Django 1.8 and upwards. Also, it should be quite a small task to adapt it to 1.5–1.7, mainly the queryset methods have changed name in those. I've put the filter itself in a core application that I have but you can obviously put it anywhere.

Implementation:

# myproject/core/admin/filters.py:

from django.contrib.admin.filters import RelatedFieldListFilter


class RelatedOnlyFieldListFilter(RelatedFieldListFilter):
    def __init__(self, field, request, params, model, model_admin, field_path):
        self.request = request
        self.model_admin = model_admin
        super(RelatedOnlyFieldListFilter, self).__init__(field, request, params, model, model_admin, field_path)

    def choices(self, cl):
        limit_choices_to = set(self.model_admin.queryset(self.request).values_list(self.field.name, flat=True))
        self.lookup_choices = [(pk_val, val) for pk_val, val in self.lookup_choices if pk_val in limit_choices_to]
        return super(RelatedOnlyFieldListFilter, self).choices(cl)

Usage:

# myapp/admin.py:

from django.contrib import admin
from myproject.core.admin.filters import RelatedOnlyFieldListFilter
from myproject.myapp.models import MyClass


class MyClassAdmin(admin.ModelAdmin):
    list_filter = (
        ('myfield', RelatedOnlyFieldListFilter),
    )

admin.site.register(MyClass, MyClassAdmin)

If you later update to Django 1.8 you should be able to just change this import:

from myproject.core.admin.filters import RelatedOnlyFieldListFilter

To this:

from django.contrib.admin.filters import RelatedOnlyFieldListFilter