Safe integer parsing in Ruby

Question

I have a string, say \'123\', and I want to convert it to the integer 123.

I know you can simply do some_string.to_i, but that

Answer 1

Re: Chris's answer

Your implementation let's things like "1a" or "b2" through. How about this instead:

def safeParse2(strToParse)
  if strToParse =~ /\A\d+\Z/
    strToParse.to_i
  else
    raise Exception
  end
end

["100", "1a", "b2", "t"].each do |number|
  begin
    puts safeParse2(number)
  rescue Exception
    puts "#{number} is invalid"
  end
end

This outputs:

100
1a is invalid
b2 is invalid
t is invalid