Google App Engine and 404 error

Question

I\'ve setup a static website on GAE using hints found elsewhere, but can\'t figure out how to return a 404 error. My app.yaml file looks like

- url: (.*)/
           


        

Answer 1

I have reviewed all the above given answers and used the following at the end as the most universal 404 solution:

Add this link at the end of app.yaml

- url: /(.*) 
  script: 404.app

and create 404.py with the following content

import webapp2
from google.appengine.ext.webapp import template

class NotFound(webapp2.RequestHandler):
  def get(self):
    self.error(404)
    self.response.out.write(template.render('404.html', {}))

app = webapp2.WSGIApplication([
    ('/.*', NotFound)
], debug=True)

This will display contents of 404.html file with 404 error code.

The advantage of this solution is simplicity, correctness of bahaviour and flexibility, as it allows to use a static 404.html file as error page content.

I also want to warn against some of the solutions suggested above.

• Custom Error Responses don not work with 404 error
• Also don't use static files, as they would return 200 instead of 404 error. This can cause a lot of headache ahead.