I have this ugly code:
if ( v > 10 ) size = 6;
if ( v > 22 ) size = 5;
if ( v > 51 ) size = 4;
if ( v > 68 ) size = 3;
if ( v > 117 ) size = 2
I have one more version for you. I don't really think it's the best one because it adds unnecessary complexity in the name of "performance" when I'm 100% sure this function will never be a performance hog (unless someone is calculating size in a tight loop a million times ...).
But I present it just because I thought performing a hard-coded binary search to be sort of interesting. It doesn't look very binary-y because there aren't enough elements to go very deep, but it does have the virtue that it returns a result in no more than 3 tests rather than 6 as in the original post. The return statements are also in order by size which would help with understanding and/or modification.
if (v > 68) {
if (v > 145) {
return 1
} else if (v > 117) {
return 2;
} else {
return 3;
}
} else {
if (v > 51) {
return 4;
} else if (v > 22) {
return 5;
} else {
return 6;
}
}