How to save traceback / sys.exc_info() values in a variable?

Question

I want to save the name of the error and the traceback details into a variable. Here\'s is my attempt.

import sys
try:
    try:
        print x
    except E         


        

Answer 1

Use traceback.extract_stack() if you want convenient access to module and function names and line numbers.

Use ''.join(traceback.format_stack()) if you just want a string that looks like the traceback.print_stack() output.

Notice that even with ''.join() you will get a multi-line string, since the elements of format_stack() contain \n. See output below.

Remember to import traceback.

Here's the output from traceback.extract_stack(). Formatting added for readability.

>>> traceback.extract_stack()
[
   ('', 1, '', None),
   ('C:\\Python\\lib\\idlelib\\run.py', 126, 'main', 'ret = method(*args, **kwargs)'),
   ('C:\\Python\\lib\\idlelib\\run.py', 353, 'runcode', 'exec(code, self.locals)'),
   ('', 1, '', None)
]

Here's the output from ''.join(traceback.format_stack()). Formatting added for readability.

>>> ''.join(traceback.format_stack())
'  File "", line 1, in \n
   File "C:\\Python\\lib\\idlelib\\run.py", line 126, in main\n
       ret = method(*args, **kwargs)\n
   File "C:\\Python\\lib\\idlelib\\run.py", line 353, in runcode\n
       exec(code, self.locals)\n  File "", line 1, in \n'