Getting parts of a URL (Regex)

Question

Given the URL (single line):
http://test.example.com/dir/subdir/file.html

How can I extract the following parts using regular expressions:

1. The Subd

Answer 1

String s = "https://www.thomas-bayer.com/axis2/services/BLZService?wsdl";

String regex = "(^http.?://)(.*?)([/\\?]{1,})(.*)";

System.out.println("1: " + s.replaceAll(regex, "$1"));
System.out.println("2: " + s.replaceAll(regex, "$2"));
System.out.println("3: " + s.replaceAll(regex, "$3"));
System.out.println("4: " + s.replaceAll(regex, "$4"));

Will provide the following output:
1: https://
2: www.thomas-bayer.com
3: /
4: axis2/services/BLZService?wsdl

If you change the URL to
String s = "https://www.thomas-bayer.com?wsdl=qwerwer&ttt=888"; the output will be the following :
1: https://
2: www.thomas-bayer.com
3: ?
4: wsdl=qwerwer&ttt=888

enjoy..
Yosi Lev