Getting parts of a URL (Regex)

Question

Given the URL (single line):
http://test.example.com/dir/subdir/file.html

How can I extract the following parts using regular expressions:

1. The Subd

Answer 1

I build this one. Very permissive it's not to check url juste divide it.

^((http[s]?):\/\/)?([a-zA-Z0-9-.]*)?([\/]?[^?#\n]*)?([?]?[^?#\n]*)?([#]?[^?#\n]*)$

• match 1 : full protocole with :// (http or https)
• match 2 : protocole without ://
• match 3 : host
• match 4 : slug
• match 5 : param
• match 6 : anchor

work

http://
https://
www.demo.com
/slug
?foo=bar
#anchor

https://demo.com
https://demo.com/
https://demo.com/slug
https://demo.com/slug/foo
https://demo.com/?foo=bar
https://demo.com/?foo=bar#anchor
https://demo.com/?foo=bar&bar=foo#anchor
https://www.greate-demo.com/

crash

#anchor#
?toto?