Getting parts of a URL (Regex)

Question

Given the URL (single line):
http://test.example.com/dir/subdir/file.html

How can I extract the following parts using regular expressions:

1. The Subd

Answer 1

Here is one that is complete, and doesnt rely on any protocol.

function getServerURL(url) {
        var m = url.match("(^(?:(?:.*?)?//)?[^/?#;]*)");
        console.log(m[1]) // Remove this
        return m[1];
    }

getServerURL("http://dev.test.se")
getServerURL("http://dev.test.se/")
getServerURL("//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js")
getServerURL("//")
getServerURL("www.dev.test.se/sdas/dsads")
getServerURL("www.dev.test.se/")
getServerURL("www.dev.test.se?abc=32")
getServerURL("www.dev.test.se#abc")
getServerURL("//dev.test.se?sads")
getServerURL("http://www.dev.test.se#321")
getServerURL("http://localhost:8080/sads")
getServerURL("https://localhost:8080?sdsa")

Prints

http://dev.test.se

http://dev.test.se

//ajax.googleapis.com

//

www.dev.test.se

www.dev.test.se

www.dev.test.se

www.dev.test.se

//dev.test.se

http://www.dev.test.se

http://localhost:8080

https://localhost:8080