Getting parts of a URL (Regex)

Question

Given the URL (single line):
http://test.example.com/dir/subdir/file.html

How can I extract the following parts using regular expressions:

1. The Subd

Answer 1

I needed a regular Expression to match all urls and made this one:

/(?:([^\:]*)\:\/\/)?(?:([^\:\@]*)(?:\:([^\@]*))?\@)?(?:([^\/\:]*)\.(?=[^\.\/\:]*\.[^\.\/\:]*))?([^\.\/\:]*)(?:\.([^\/\.\:]*))?(?:\:([0-9]*))?(\/[^\?#]*(?=.*?\/)\/)?([^\?#]*)?(?:\?([^#]*))?(?:#(.*))?/

It matches all urls, any protocol, even urls like

ftp://user:pass@www.cs.server.com:8080/dir1/dir2/file.php?param1=value1#hashtag

The result (in JavaScript) looks like this:

["ftp", "user", "pass", "www.cs", "server", "com", "8080", "/dir1/dir2/", "file.php", "param1=value1", "hashtag"]

An url like

mailto://admin@www.cs.server.com

looks like this:

["mailto", "admin", undefined, "www.cs", "server", "com", undefined, undefined, undefined, undefined, undefined]