This is a programming question asked during a written test for an interview. \"You have two singly linked lists that are already sorted, you have to merge them and return a
/* Simple/Elegant Iterative approach in Java*/
private static LinkedList mergeLists(LinkedList list1, LinkedList list2) {
Node head1 = list1.start;
Node head2 = list2.start;
if (list1.size == 0)
return list2;
if (list2.size == 0)
return list1;
LinkedList mergeList = new LinkedList();
while (head1 != null && head2 != null) {
if (head1.getData() < head2.getData()) {
int data = head1.getData();
mergeList.insert(data);
head1 = head1.getNext();
} else {
int data = head2.getData();
mergeList.insert(data);
head2 = head2.getNext();
}
}
while (head1 != null) {
int data = head1.getData();
mergeList.insert(data);
head1 = head1.getNext();
}
while (head2 != null) {
int data = head2.getData();
mergeList.insert(data);
head2 = head2.getNext();
}
return mergeList;
}
/* Build-In singly LinkedList class in Java*/
class LinkedList {
Node start;
int size = 0;
void insert(int data) {
if (start == null)
start = new Node(data);
else {
Node temp = start;
while (temp.getNext() != null) {
temp = temp.getNext();
}
temp.setNext(new Node(data));
}
size++;
}
@Override
public String toString() {
String str = "";
Node temp=start;
while (temp != null) {
str += temp.getData() + "-->";
temp = temp.getNext();
}
return str;
}
}