How to use > in an xargs command?

Question

I want to find a bash command that will let me grep every file in a directory and write the output of that grep to a separate file. My guess would have been to do something

Answer 1

A solution without xargs is the following:

find . -mindepth 1 -maxdepth 1 -type f -exec sh -c "grep ABC '{}' > '{}.out'" \;

...and the same can be done with xargs, it turns out:

ls -1 | xargs -I {} sh -c "grep ABC '{}' > '{}.out'"

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Edit: single quotes added after remark by lhunath.