I\'m trying to extract URLs from a sitemap like this: https://www.bestbuy.com/sitemap_c_0.xml.gz
I\'ve unzipped and saved the .xml.gz file as an .xml file. The struc
You were close in your attempt but like mzjn said in a comment, you didn't account for the default namespace (xmlns="http://www.sitemaps.org/schemas/sitemap/0.9"
).
Here's an example of how to account for the namespace:
import xml.etree.ElementTree as ET
tree = ET.parse('my_local_filepath')
ns = {"sm": "http://www.sitemaps.org/schemas/sitemap/0.9"}
for elem in tree.findall(".//sm:loc", ns):
print(elem.text)
output:
https://www.bestbuy.com/
https://www.bestbuy.com/site/3d-printers/3d-printer-filament/pcmcat335400050008.c?id=pcmcat335400050008
https://www.bestbuy.com/site/3d-printers/3d-printing-accessories/pcmcat748300527647.c?id=pcmcat748300527647
Note that I used the namespace prefix sm
, but you could use any NCName.
See here for more information on parsing XML with namespaces in ElementTree.