read subprocess stdout line by line

Question

My python script uses subprocess to call a linux utility that is very noisy. I want to store all of the output to a log file and show some of it to the user. I thought the

Answer 1

A function that allows iterating over both stdout and stderr concurrently, in realtime, line by line

In case you need to get the output stream for both stdout and stderr at the same time, you can use the following function.

The function uses Queues to merge both Popen pipes into a single iterator.

Here we create the function read_popen_pipes():

from queue import Queue, Empty
from concurrent.futures import ThreadPoolExecutor


def enqueue_output(file, queue):
    for line in iter(file.readline, ''):
        queue.put(line)
    file.close()


def read_popen_pipes(p):

    with ThreadPoolExecutor(2) as pool:
        q_stdout, q_stderr = Queue(), Queue()

        pool.submit(enqueue_output, p.stdout, q_stdout)
        pool.submit(enqueue_output, p.stderr, q_stderr)

        while True:

            if p.poll() is not None and q_stdout.empty() and q_stderr.empty():
                break

            out_line = err_line = ''

            try:
                out_line = q_stdout.get_nowait()
            except Empty:
                pass
            try:
                err_line = q_stderr.get_nowait()
            except Empty:
                pass

            yield (out_line, err_line)

read_popen_pipes() in use:

import subprocess as sp


with sp.Popen(my_cmd, stdout=sp.PIPE, stderr=sp.PIPE, text=True) as p:

    for out_line, err_line in read_popen_pipes(p):

        # Do stuff with each line, e.g.:
        print(out_line, end='')
        print(err_line, end='')

    return p.poll() # return status-code