How to create the most compact mapping n → isprime(n) up to a limit N?

Question

Naturally, for bool isprime(number) there would be a data structure I could query.
I define the best algorithm, to be the algorithm that pr

Answer 1

bool isPrime(int n) {
if(n <= 3)
    return (n > 1)==0? false: true;
else if(n%2 == 0 || n%3 == 0)
    return false;

int i = 5;

while(i * i <= n){
    if(n%i == 0 || (n%(i+2) == 0))
        return false;
    i = i + 6;
}

return true;
}

for any number, the minimum iterations to check if the number is prime or not can be from 2 to square root of the number. To reduce the iterations, even more, we can check if the number is divisible by 2 or 3 as maximum numbers can be eliminated by checking if the number is divisible by 2 or 3. Further any prime number greater than 3 can be expressed as 6k+1 or 6k-1. So the iteration can go from 6k+1 to the square root of the number.