How to let the sortedArrayUsingSelector using integer to sort instead of String?

Question

I have some data like this :

1, 111, 2, 333, 45, 67, 322, 4445

NSArray *array = [[myData allKeys]sortedArrayUsingSelector: @selector(compare:)];
         


        

Answer 1

David's answer did the trick for me. For what it's worth, I want to share the Swift 1.0 version of the same answer.

extension NSString {
    func psuedoNumericCompare(otherString: NSString) -> NSComparisonResult {
        var left: NSString = self
        var right: NSString = otherString
        var leftNumber: Int = self.integerValue
        var rightNumber: Int = otherString.integerValue

        var leftScanner: NSScanner = NSScanner(string: left)
        var rightScanner: NSScanner = NSScanner(string: right)

        if leftScanner.scanInteger(&leftNumber) && rightScanner.scanInteger(&rightNumber) {
            if leftNumber < rightNumber {
                return NSComparisonResult.OrderedAscending
            }
            if leftNumber > rightNumber {
                return NSComparisonResult.OrderedDescending
            }

            left = left.substringFromIndex(leftScanner.scanLocation)
            right = right.substringFromIndex(rightScanner.scanLocation)
        }
        return left.caseInsensitiveCompare(right)
    }
}