RegEx: Grabbing values between quotation marks

Question

I have a value like this:

\"Foo Bar\" \"Another Value\" something else

What regex will return the

Answer 1

I liked Axeman's more expansive version, but had some trouble with it (it didn't match for example

foo "string \\ string" bar

or

foo "string1"   bar   "string2"

correctly, so I tried to fix it:

# opening quote
(["'])
   (
     # repeat (non-greedy, so we don't span multiple strings)
     (?:
       # anything, except not the opening quote, and not 
       # a backslash, which are handled separately.
       (?!\1)[^\\]
       |
       # consume any double backslash (unnecessary?)
       (?:\\\\)*       
       |
       # Allow backslash to escape characters
       \\.
     )*?
   )
# same character as opening quote
\1