RegEx: Grabbing values between quotation marks

Question

I have a value like this:

\"Foo Bar\" \"Another Value\" something else

What regex will return the

Answer 1

The RegEx of accepted answer returns the values including their sourrounding quotation marks: "Foo Bar" and "Another Value" as matches.

Here are RegEx which return only the values between quotation marks (as the questioner was asking for):

Double quotes only (use value of capture group #1):

"(.*?[^\\])"

Single quotes only (use value of capture group #1):

'(.*?[^\\])'

Both (use value of capture group #2):

(["'])(.*?[^\\])\1

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All support escaped and nested quotes.