PHP syntax error “unexpected $end”

Question

I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php

1) First file is for creating a new table for a data base, it is a fom with 2 input

Answer 1

$result = mysql_query($sql, $connection) or die(mysql_error());
if ($result) {
    $msg = "
" .$_POST[table_name]." has been created!
";
}

you missing a } in your last if statement, and your for loop is missing a } too

for ($i = 0; $i < count($_POST[field_name]); $i++) {
    $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
    if ($_POST[field_length][$i] !="") {
      $sql .=" (".$_POST[field_length][$i]."),";
    } else {
        $sql .=",";
    }
}