Why do two functions have the same address?

Question

Consider this function template:

template
unsigned long f(void *) { return 0;}

Now, I print the addresses of f

Answer 1

This is simply a case of undefined behavior because the results of casting a pointer to a function to a pointer to object type are undefined.

A more interesting expression to examine would bef == f which should evaluate to true if and only if A and B refer to the same type.