Why do two functions have the same address?

Question

Consider this function template:

template
unsigned long f(void *) { return 0;}

Now, I print the addresses of f

Answer 1

You need to cast to void *:

std::cout << (void*)(ftype*)f << std::endl;
std::cout << (void*)(ftype*)f << std::endl;

If you cast to a function pointer (or several other classes of non-void pointers), it will be interpreted as a bool by the operator<< for std::ostream (hence the 1).