Fahrenheit to Celsius conversion yields only 0.0 and -0.0

Question

I\'m on the 8th chapter (Methods, Constructors, and Fields) of my Java methods book and I\'m having a problem with one of my exercises.

The provided code is Tempera

Answer 1

In integer math (5 / 9) = 0.

and (degrees - 32) * (5 / 9); will always be 0 you need to use doubles or something.