permutations with unique values

Question

itertools.permutations generates where its elements are treated as unique based on their position, not on their value. So basically I want to avoid duplicates like this:

Answer 1

What about

np.unique(itertools.permutations([1, 1, 1]))

The problem is the permutations are now rows of a Numpy array, thus using more memory, but you can cycle through them as before

perms = np.unique(itertools.permutations([1, 1, 1]))
for p in perms:
    print p