C# decimal take ceiling 2

Question

I want to round my decimal value like 2.2222 to 2.23. When I use round,

decimal a = Math.Round((decimal)2.222, 2);

When I use ceiling, it c

Answer 1

I solved my problem..

 string n = "2.2222";
        string[] s = n.Split('.');

        if (s[1].Count() >= 3)
        {
            List z = s[1].ToString().Take(2).ToList();
            int c=Convert.ToInt32(z[0].ToString() + z[1].ToString()) + 1;
          //  int b = Convert.ToInt32(s[1].ElementAt(0).ToString() + s[1].ElementAt(1).ToString()) + 1;
            string output= s[0] + "." + c.ToString();            
        }

now any number can put ,it will take 2 decimal value and add 1.Thanks.