C++ declare an array based on a non-constant variable?

Question

void method(string a) {
  int n = a.size();
  int array[n];
}

The above code can compile correctly using gcc. How can the size of the array come fr

Answer 1

dynamic allocation. The new keyword will do this with a pointer and some allocation.

int * ptr;
int n = a.size();
ptr = new int[n];