Given a DateTime object, how do I get an ISO 8601 date in string format?

Question

Given:

DateTime.UtcNow

How do I get a string which represents the same value in an ISO 8601-compliant format?

Note that ISO 8601 de

Answer 1

You can get the "Z" (ISO 8601 UTC) with the next code:

Dim tmpDate As DateTime = New DateTime(Now.Ticks, DateTimeKind.Utc)
Dim res as String = tmpDate.toString("o") '2009-06-15T13:45:30.0000000Z

Here is why:

The ISO 8601 have some different formats:

DateTimeKind.Local

2009-06-15T13:45:30.0000000-07:00

DateTimeKind.Utc

2009-06-15T13:45:30.0000000Z

DateTimeKind.Unspecified

2009-06-15T13:45:30.0000000

.NET provides us with an enum with those options:

'2009-06-15T13:45:30.0000000-07:00
Dim strTmp1 As String = New DateTime(Now.Ticks, DateTimeKind.Local).ToString("o")

'2009-06-15T13:45:30.0000000Z
Dim strTmp2 As String = New DateTime(Now.Ticks, DateTimeKind.Utc).ToString("o")

'2009-06-15T13:45:30.0000000
Dim strTmp3 As String = New DateTime(Now.Ticks, DateTimeKind.Unspecified).ToString("o")

Note: If you apply the Visual Studio 2008 "watch utility" to the toString("o") part you may get different results, I don't know if it's a bug, but in this case you have better results using a String variable if you're debugging.

Source: Standard Date and Time Format Strings (MSDN)