Windows console

Question

I would like to set the date in a Windows batch file to 7 days ago from today. I would like to do this in the following format.

Answer 1

Ok, I needed a batch file to display the current JDAY for an DoD operations center. You can double-click the file and it will display in a CMD window. Then, press any key to exit.

Here's what I came up with:

@echo off
for /f "tokens=2 delims==" %%a in ('wmic OS Get localdatetime /value')     do set "dt=%%a"
set "YY=%dt:~2,2%" & set "YYYY=%dt:~0,4%" & set "MM=%dt:~4,2%" & set     "DD=%dt:~6,2%"
set "HH=%dt:~8,2%" & set "Min=%dt:~10,2%" & set "Sec=%dt:~12,2%"

:: Call the day ordinal number subroutine
call :JDdayNumber %DD% %MM% %YYYY% DayOrdinalNumber

:: Display the result
echo.
echo Today is JDay %DayOrdinalNumber%
echo.
pause,
endlocal & goto :EOF

:: set "datestamp=%YYYY%%MM%%DD%" & set "timestamp=%HH%%Min%%Sec%"
:: set "fullstamp=%YYYY%-%MM%-%DD%_%HH%-%Min%-%Sec%"
:: echo datestamp: "%datestamp%"
:: echo timestamp: "%timestamp%"
:: echo fullstamp: "%fullstamp%"

:: ============================================================
:: Subroutine: Calculate a day's ordinal number within the year
::JDdayNumber day month year return_
setlocal enableextensions enabledelayedexpansion
if %2 LEQ 2 (
set /a f=%1-1+31*^(%2-1^)
) else (
set /a a=%3
set /a b=!a!/4-!a!/100+!a!/400
set /a c=^(!a!-1^)/4-^(!a!-1^)/100+^(!a!-1^)/400
set /a s=!b!-!c!
set /a f=%1+^(153*^(%2-3^)+2^)/5+58+!s!
)
set /a return_=%f%+1
endlocal & set "%4=%return_%" & goto :EOF